Rectangle Has An Area Of 8x^5y^3 And A Length Of 4x^2y^3 What Is The Width

Rectangle has an area of 8x^5y^3 and a length of 4x^2y^3 what is the width

Answer:

$2 {x}^{3} units$

Formula for area of rectangle:

$l \: \times w$

Finding the width:

$\frac{area}{length}$

Substitute:

$\frac{8 {x}^{5}{y}^{3} }{4 {x}^{2} {y}^{3} }$

Cancel:

$\frac{8 {x}^{5} }{4{x}^{2} }$

Divide:

$2 {x}^{3}$

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