Rectangle Has An Area Of 8x^5y^3 And A Length Of 4x^2y^3 What Is The Width

Rectangle has an area of 8x^5y^3 and a length of 4x^2y^3 what is the width

Answer:

2 {x}^{3} units

Formula for area of rectangle:

l \:  \times w

Finding the width:

 \frac{area}{length}

Substitute:

 \frac{8 {x}^{5}{y}^{3} }{4 {x}^{2} {y}^{3}  }

Cancel:

 \frac{8 {x}^{5} }{4{x}^{2} }

Divide:

2 {x}^{3}


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